The radical,$C_6H_5CH_2^{\bullet}$,is aromatic because it has

  • A
    $7 \ p$-orbitals and $7$ unpaired electrons
  • B
    $6 \ p$-orbitals and $7$ unpaired electrons
  • C
    $6 \ p$-orbitals and $6$ unpaired electrons
  • D
    $7 \ p$-orbitals and $6$ unpaired electrons

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